CoCoA:HowTo:Use Modular Numbers: Difference between revisions
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== | == Question == | ||
How can one compute with modular numbers? What's wrong in this? | |||
Use R::=Z/(5)[x]; | Use R::=Z/(5)[x]; | ||
5x+2y; | 5x+2y; | ||
2y | 2y | ||
--- | ------------------------------- | ||
5=0; | 5=0; | ||
FALSE | FALSE | ||
--- | ------------------------------- | ||
Moreover this command throws an error | |||
Use R::=Z/(5); | |||
== Answer == | |||
Type(5); | |||
INT | |||
INT | ------------------------------- | ||
------------------------------- | 5 is an integer, and integers do not depend on the current ring: could you imagine what would happen to a For cycle over Z/(2)? ;-) | ||
5 | |||
If you want to use 5 as a modular number you should either use this syntax (similar to C/C++) | |||
5 % 5; | |||
0 % 5 | 0 % 5 | ||
------------------------------- | ------------------------------- | ||
or embed your integer into the polynomial ring | |||
Use R::=Z/(5)[x]; | |||
Poly(5); | |||
0 | 0 | ||
------------------------------- | ------------------------------- | ||
The creation of a polynomial ring with no indeterminates has been disabled to highlight this (unexpected?) behaviour. | |||
by [[User:Bigatti|Bigatti]] 17:26, 29 Nov 2005 (CET) | |||
[[Category:HowTo Old]] | |||
[[Category:CoCoA4]] |
Latest revision as of 09:44, 29 October 2020
Question
How can one compute with modular numbers? What's wrong in this?
Use R::=Z/(5)[x]; 5x+2y; 2y ------------------------------- 5=0; FALSE -------------------------------
Moreover this command throws an error
Use R::=Z/(5);
Answer
Type(5); INT -------------------------------
5 is an integer, and integers do not depend on the current ring: could you imagine what would happen to a For cycle over Z/(2)? ;-)
If you want to use 5 as a modular number you should either use this syntax (similar to C/C++)
5 % 5; 0 % 5 -------------------------------
or embed your integer into the polynomial ring
Use R::=Z/(5)[x]; Poly(5); 0 -------------------------------
The creation of a polynomial ring with no indeterminates has been disabled to highlight this (unexpected?) behaviour.
by Bigatti 17:26, 29 Nov 2005 (CET)